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x^2+12.5x-18.75=0
a = 1; b = 12.5; c = -18.75;
Δ = b2-4ac
Δ = 12.52-4·1·(-18.75)
Δ = 231.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12.5)-\sqrt{231.25}}{2*1}=\frac{-12.5-\sqrt{231.25}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12.5)+\sqrt{231.25}}{2*1}=\frac{-12.5+\sqrt{231.25}}{2} $
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